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面试题 16.15. 珠玑妙算
阅读量:536 次
发布时间:2019-03-08

本文共 2479 字,大约阅读时间需要 8 分钟。

珠玑妙算游戏(the game of master mind)的玩法如下。

计算机有4个槽,每个槽放一个球,颜色可能是红色(R)、黄色(Y)、绿色(G)或蓝色(B)。例如,计算机可能有RGGB 4种(槽1为红色,槽2、3为绿色,槽4为蓝色)。作为用户,你试图猜出颜色组合。打个比方,你可能会猜YRGB。要是猜对某个槽的颜色,则算一次“猜中”;要是只猜对颜色但槽位猜错了,则算一次“伪猜中”。注意,“猜中”不能算入“伪猜中”。

给定一种颜色组合solution和一个猜测guess,编写一个方法,返回猜中和伪猜中的次数answer,其中answer[0]为猜中的次数,answer[1]为伪猜中的次数。

示例:

输入: solution="RGBY",guess="GGRR"输出: [1,1]解释: 猜中1次,伪猜中1次。

提示:

  • len(solution) = len(guess) = 4
  • solutionguess仅包含"R","G","B","Y"这4种字符
package Solutionmst1615;import java.util.Arrays;class Solution {	public int[] masterMind(String solution, String guess) {		int guessRcount = 0;		int guessYcount = 0;		int guessGcount = 0;		int guessBcount = 0;		int solutionRcount = 0;		int solutionYcount = 0;		int solutionGcount = 0;		int solutionBcount = 0;		for (int i = 0; i < guess.length(); i++) {			if (guess.charAt(i) == 'R') {				guessRcount++;			}			if (guess.charAt(i) == 'Y') {				guessYcount++;			}			if (guess.charAt(i) == 'G') {				guessGcount++;			}			if (guess.charAt(i) == 'B') {				guessBcount++;			}		}		for (int i = 0; i < solution.length(); i++) {			if (solution.charAt(i) == 'R') {				solutionRcount++;			}			if (solution.charAt(i) == 'Y') {				solutionYcount++;			}			if (solution.charAt(i) == 'G') {				solutionGcount++;			}			if (solution.charAt(i) == 'B') {				solutionBcount++;			}		}		int[] out = new int[2];		for (int i = 0; i < guess.length(); i++) {			for (int j = 0; j < solution.length(); j++) {				if (guess.charAt(i) == solution.charAt(j) && i == j) {					if (solution.charAt(i) == 'R') {						solutionRcount--;						guessRcount--;					}					if (solution.charAt(i) == 'Y') {						solutionYcount--;						guessYcount--;					}					if (solution.charAt(i) == 'G') {						solutionGcount--;						guessGcount--;					}					if (solution.charAt(i) == 'B') {						solutionBcount--;						guessBcount--;					}					out[0]++;				}			}		}		if (guessRcount > 0 && solutionRcount > 0) {			out[1] = out[1] + Math.min(guessRcount, solutionRcount);		}		if (guessYcount > 0 && solutionYcount > 0) {			out[1] = out[1] + Math.min(guessYcount, solutionYcount);		}		if (guessGcount > 0 && solutionGcount > 0) {			out[1] = out[1] + Math.min(guessGcount, solutionGcount);		}		if (guessBcount > 0 && solutionBcount > 0) {			out[1] = out[1] + Math.min(guessBcount, solutionBcount);		}		return out;	}	public static void main(String[] args) {		Solution sol = new Solution();		String solution = "YBBY", guess = "GYYB";		System.out.println(Arrays.toString(sol.masterMind(solution, guess)));	}}

 

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